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Syntax-abstraction

Abs-assignment-statement

Abstract an assignment-statement to a statement.

Signature
(abs-assignment-statement tree) → stat
Arguments: tree — Guard (abnf::treep tree).
Returns: stat — Type (statement-resultp stat).

Definitions and Theorems

Function: abs-assignment-statement

(defun abs-assignment-statement (tree)
  (declare (xargs :guard (abnf::treep tree)))
  (let ((__function__ 'abs-assignment-statement))
    (declare (ignorable __function__))
    (b* (((okf (abnf::tree-list-tuple4 sub))
          (abnf::check-tree-nonleaf-4 tree "assignment-statement"))
         ((okf tree)
          (abnf::check-tree-list-1 sub.1st))
         ((okf left) (abs-expression tree))
         ((okf tree)
          (abnf::check-tree-list-1 sub.2nd))
         ((okf op)
          (abs-assignment-operator tree))
         ((okf tree)
          (abnf::check-tree-list-1 sub.3rd))
         ((okf right) (abs-expression tree))
         ((okf tree)
          (abnf::check-tree-list-1 sub.4th))
         ((okf &)
          (abnf::check-tree-ichars tree ";")))
      (make-statement-assign :op op
                             :left left
                             :right right))))

Theorem: statement-resultp-of-abs-assignment-statement

(defthm statement-resultp-of-abs-assignment-statement
  (b* ((stat (abs-assignment-statement tree)))
    (statement-resultp stat))
  :rule-classes :rewrite)

Theorem: abs-assignment-statement-of-tree-fix-tree

(defthm abs-assignment-statement-of-tree-fix-tree
  (equal (abs-assignment-statement (abnf::tree-fix tree))
         (abs-assignment-statement tree)))

Theorem: abs-assignment-statement-tree-equiv-congruence-on-tree

(defthm abs-assignment-statement-tree-equiv-congruence-on-tree
  (implies (abnf::tree-equiv tree tree-equiv)
           (equal (abs-assignment-statement tree)
                  (abs-assignment-statement tree-equiv)))
  :rule-classes :congruence)